Lesson 3 · 40 min

Estimating L/D from the Sketch

The Breguet equations need a lift-to-drag ratio, but there is no drag analysis yet: only a sketch. Fortunately, the sketch already holds the two numbers that matter most, the span and the wetted area. Together with a skin-friction coefficient typical of the class, they give an \(\LDmax\) good enough to size the aircraft, long before a full drag build-up is possible.

Learning objectives

Wetted area from the sketch

Zero-lift drag at subsonic speeds is mostly skin friction, so it grows with the area the air touches: the wetted area \(\Swet\). Quick estimates come from the views of a sketch:

Wetted area (quick approximations)

\[ \text{Wings and tails:}\ \ \Swet \approx S_{\text{exposed}}\left(1.977 + 0.52\,\tfrac{t}{c}\right) \] \[ \text{Fuselage:}\ \ \Swet \approx 3.4\,\frac{A_{\text{top}} + A_{\text{side}}}{2} \]

\(S_{\text{exposed}}\) is the planform area outside the fuselage; a little more than twice this area is wetted (top and bottom, plus a thickness correction). \(A_{\text{top}}\) and \(A_{\text{side}}\) are the projected areas of the fuselage in the top and side views. Add nacelles, pods and external stores the same way.

Example 3.1 — The business jet's wetted area

The sketch shows a wing of \(\Sref = 28\ \text{m}^2\) and aspect ratio 8, of which 85% is exposed, with \(t/c = 0.12\); exposed tails of \(6.0\ \text{m}^2\) (horizontal) and \(4.5\ \text{m}^2\) (vertical) with \(t/c = 0.10\); a fuselage \(14\ \text{m}\) long and \(1.8\ \text{m}\) in diameter whose top and side views each cover 85% of the bounding rectangle; and two nacelles of \(6\ \text{m}^2\) wetted area each. Find the total wetted area and \(\Swet/\Sref\).

Show solution
\[ \text{Wing: } 0.85(28)(1.977 + 0.52(0.12)) = 23.8(2.039) = 48.5\ \text{m}^2 \] \[ \text{Tails: } (6.0 + 4.5)(1.977 + 0.052) = 21.3\ \text{m}^2 \] \[ A_{\text{top}} = A_{\text{side}} = 0.85(14)(1.8) = 21.4\ \text{m}^2, \qquad \text{fuselage: } 3.4(21.4) = 72.8\ \text{m}^2 \]
Wetted area build-up
Component\(\Swet\) (m²)Share
Wing48.531%
Tails21.314%
Fuselage72.847%
Nacelles12.08%
Total154.7100%
\[ \frac{\Swet}{\Sref} = \frac{154.7}{28} = 5.52 \approx 5.5 \]

Almost half the wetted area of a business jet is fuselage: a small aircraft must still have a cabin people can sit in. That is one reason small jets have lower \(L/D\) than airliners.

Zero-lift drag: the equivalent skin friction

Real aircraft have more drag than flat-plate skin friction alone: form drag, interference, gaps, antennas, leakage. These are all lumped into an equivalent skin-friction coefficient \(C_{fe}\), measured on existing aircraft of each type:

Equivalent skin-friction method

\[ \CDz = C_{fe}\,\frac{\Swet}{\Sref} \]
Equivalent skin-friction coefficients for subsonic flight (source: Raymer, Table 12.3)
Type of aircraft\(C_{fe}\)

Light aircraft have higher \(C_{fe}\) than airliners: fixed landing gear, exposed engines, less careful finish and, above all, a lower Reynolds number, at which skin friction is higher.

The wetted aspect ratio

Substitute \(\CDz = C_{fe}\Swet/\Sref\) into Module 1's \(\LDmax = \tfrac12\sqrt{\pi A e/\CDz}\), with \(A = b^2/\Sref\). The reference area cancels:

Maximum \(L/D\) from the sketch

\[ A_{\text{wet}} = \frac{b^2}{\Swet} = \frac{A}{\Swet/\Sref}, \qquad \LDmax = \frac12\sqrt{\frac{\pi e\,\colL{A_{\text{wet}}}}{C_{fe}}} \]

Span gives lift efficiently (induced drag falls with \(b^2\)); wetted area costs friction drag. Their ratio is what matters. Take \(e\) about 0.75 to 0.85 for a first estimate (Module 9 estimates it properly).

Plotted against \(A_{\text{wet}}\), the \(\LDmax\) of real aircraft falls in a band for each class, and a first estimate can be read off the band. The formula above is the physics behind those bands; it is a little optimistic because it ignores trim, compressibility and the drag of things the sketch does not show, so many designers take a few percent off.

Example 3.2 — The business jet's \(L/D\)

With \(A = 8\), \(\Swet/\Sref = 5.5\), \(C_{fe} = 0.0030\) (civil transport) and \(e = 0.75\), find \(A_{\text{wet}}\), \(\CDz\), \(\LDmax\), and the \(L/D\) to use in cruise.

Show solution
\[ A_{\text{wet}} = \frac{8}{5.5} = 1.455, \qquad \CDz = 0.0030(5.5) = 0.0165 \] \[ \LDmax = \frac12\sqrt{\frac{\pi(0.75)(1.455)}{0.0030}} = \frac12\sqrt{1142} = 16.9 \]

A jet gets its best range at \(L/D = 0.866\,\LDmax\) (Module 1, Lesson 6), so cruise uses \(0.866(16.9) = 14.6\). The 45-minute loiter reserve uses \(\LDmax = 16.9\).

Figure 3.3 \(\LDmax\) against wetted aspect ratio, \(\tfrac12\sqrt{\pi e A_{\text{wet}}/C_{fe}}\), for each type of aircraft in the \(C_{fe}\) table (gray), with the chosen type in blue. Set the aspect ratio and the wetted-area ratio of a sketch to place it. A longer span helps; a bigger fuselage for the same wing hurts.

Which \(L/D\) for cruise and loiter

An aircraft does not fly every segment at \(\LDmax\). What it maximizes depends on how its fuel consumption varies with speed:

\(L/D\) for the Breguet segments
EngineCruise (best range)Loiter (best endurance)
Jet\(0.866\,\LDmax\)\(\LDmax\)
Propeller\(\LDmax\)\(0.866\,\LDmax\)

A jet burns fuel in proportion to thrust, so it loiters where drag is least (\(\LDmax\)) and cruises a little faster, where speed times \(L/D\) is greatest. A propeller engine burns fuel in proportion to power, drag times speed, so it cruises at \(\LDmax\) and loiters slower, where power is least, at \(0.866\,\LDmax\). Lesson 4 shows why from the fuel consumption.

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Key takeaways